264=w^2-2w

Solution for 264=w^2-2w equation:

264=w^2-2w

We move all terms to the left:

264-(w^2-2w)=0

We get rid of parentheses

-w^2+2w+264=0

We add all the numbers together, and all the variables

-1w^2+2w+264=0

a = -1; b = 2; c = +264;
Δ = b2-4ac
Δ = 22-4·(-1)·264
Δ = 1060
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1060}=\sqrt{4*265}=\sqrt{4}*\sqrt{265}=2\sqrt{265}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2\sqrt{265}}{2*-1}=\frac{-2-2\sqrt{265}}{-2}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2\sqrt{265}}{2*-1}=\frac{-2+2\sqrt{265}}{-2}
$